Juce_dsp read access violation General JUCE discussion JUCE
Read Access Violation. So, i get through adding to the front twice, and creating the new node insert_rear () as well as the first iteration of the while loop. Check the value returned by test.c_str () and verify you can read from that address.
Juce_dsp read access violation General JUCE discussion JUCE
(remmember, c doesn't have strings, it has character arrays.) then, in your second loop, you get an access violation because you're trying to index past the end of the array. A b instance on the stack would do just fine. Check the value returned by test.c_str () and verify you can read from that address. List is not empty, and there is no tail. If you have no malware on your computer, you can add the program that. Inspect your computer for a malware infection. } you could be calling toupper to change to upper case and assigning the value back to *sname instead of having the function call itself. You will only be writing/reading the pointer values, not the actual character data. So, i get through adding to the front twice, and creating the new node insert_rear () as well as the first iteration of the while loop. Web 1 day agothere are now 2 items in the list.
You have to allocate a b with make_shared: Web assigning values for both wizards and both spells are fine. Then it points me to my method in node.cpp that is node* node::getnext () const { return m_next; You're running past yourself with your loops. Then when it goes into the battle loop, this error pops up: I'm guessing there's no device at that address to read from because test is an empty string. Std::_string_alloc<std::_string_base_types<char,std::allocator<char> > >::_get_data (.) returned nullptr. Check the value returned by test.c_str () and verify you can read from that address. B () {.} just initializes the shared_ptr instance. As such, you will not be able to write/read person objects using ofstream::write() and ifstream::read() the way you are trying to do. Inspect your computer for a malware infection.